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Hi Daniele, thanks a lot for answering. > how those numbers compare with the fit results? It looks like they are > worse that the fit ones. They are not a result of an mes fit (I suppose), > then I would say that the differences are all in the combinatorics (that > is consistent with a removal of BAD breco modes). There was no mes fit, we just compared the bare reduced ntuples, no other cuts than shown in the table. > another point. Which is the option "-d" you are using? -4 or -8. If you > have -4 you will pick up only events with a lepton. Even the number > of events with |Gvxbtyp|==7 can depend on this. Most of the time we were using -d 4. Is that what you used for your reduced ntuples? Recently we put in another possibility of -d 16 which only writes out events with fVub>0 (since we got D and D* and D** peaks in mxhadgen which we picked up from the other side when the signal lepton was a tau) and this actually makes us loose some leptons and events with |Gvxbtyp|!=7 (I just recognized this..). Thanks for the hint. > > Ric mentioned earlier that small differences can be due to minor changes > > in the (Breco) code. But we think Alessio said that the instructions page > > for IslBrecoilUser has the tags that you actually used when producing your > > ntuples. We used the tags given there as well. If we used the same tags, > > how can we get differences in the ntuples? > > > > One more question about the Gvxbtyp variable as it is filled in > > mcTruth.icc: > > If two semileptonic B decays are present in one event Gvxbtyp is set to > > the value that corresponds to one of these decays while the information > > about the other one is lost for this variable (e.g. in your nonres file, > > there are events for which this variable is not 7 or -7 although each of > > the events contains one b B -> X_u l nu decay). Why are you doing it this > > way? > > in general, when you have two semiletponic decays, you will not have any > peak in mes. Then, if you extract your yields by mes fit, those cases are > not interesting at all (they will be subtracted). Ok, thanks, Kerstin